3.1244 \(\int \frac{1}{x^3 \left (a-b x^4\right )^{3/4}} \, dx\)

Optimal. Leaf size=85 \[ \frac{\sqrt{b} \left (1-\frac{b x^4}{a}\right )^{3/4} F\left (\left .\frac{1}{2} \sin ^{-1}\left (\frac{\sqrt{b} x^2}{\sqrt{a}}\right )\right |2\right )}{2 \sqrt{a} \left (a-b x^4\right )^{3/4}}-\frac{\sqrt [4]{a-b x^4}}{2 a x^2} \]

[Out]

-(a - b*x^4)^(1/4)/(2*a*x^2) + (Sqrt[b]*(1 - (b*x^4)/a)^(3/4)*EllipticF[ArcSin[(
Sqrt[b]*x^2)/Sqrt[a]]/2, 2])/(2*Sqrt[a]*(a - b*x^4)^(3/4))

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Rubi [A]  time = 0.113596, antiderivative size = 85, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25 \[ \frac{\sqrt{b} \left (1-\frac{b x^4}{a}\right )^{3/4} F\left (\left .\frac{1}{2} \sin ^{-1}\left (\frac{\sqrt{b} x^2}{\sqrt{a}}\right )\right |2\right )}{2 \sqrt{a} \left (a-b x^4\right )^{3/4}}-\frac{\sqrt [4]{a-b x^4}}{2 a x^2} \]

Antiderivative was successfully verified.

[In]  Int[1/(x^3*(a - b*x^4)^(3/4)),x]

[Out]

-(a - b*x^4)^(1/4)/(2*a*x^2) + (Sqrt[b]*(1 - (b*x^4)/a)^(3/4)*EllipticF[ArcSin[(
Sqrt[b]*x^2)/Sqrt[a]]/2, 2])/(2*Sqrt[a]*(a - b*x^4)^(3/4))

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Rubi in Sympy [A]  time = 13.5898, size = 68, normalized size = 0.8 \[ - \frac{\sqrt [4]{a - b x^{4}}}{2 a x^{2}} + \frac{\sqrt{b} \left (1 - \frac{b x^{4}}{a}\right )^{\frac{3}{4}} F\left (\frac{\operatorname{asin}{\left (\frac{\sqrt{b} x^{2}}{\sqrt{a}} \right )}}{2}\middle | 2\right )}{2 \sqrt{a} \left (a - b x^{4}\right )^{\frac{3}{4}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate(1/x**3/(-b*x**4+a)**(3/4),x)

[Out]

-(a - b*x**4)**(1/4)/(2*a*x**2) + sqrt(b)*(1 - b*x**4/a)**(3/4)*elliptic_f(asin(
sqrt(b)*x**2/sqrt(a))/2, 2)/(2*sqrt(a)*(a - b*x**4)**(3/4))

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Mathematica [C]  time = 0.0489164, size = 70, normalized size = 0.82 \[ \frac{b x^4 \left (1-\frac{b x^4}{a}\right )^{3/4} \, _2F_1\left (\frac{1}{2},\frac{3}{4};\frac{3}{2};\frac{b x^4}{a}\right )-2 a+2 b x^4}{4 a x^2 \left (a-b x^4\right )^{3/4}} \]

Antiderivative was successfully verified.

[In]  Integrate[1/(x^3*(a - b*x^4)^(3/4)),x]

[Out]

(-2*a + 2*b*x^4 + b*x^4*(1 - (b*x^4)/a)^(3/4)*Hypergeometric2F1[1/2, 3/4, 3/2, (
b*x^4)/a])/(4*a*x^2*(a - b*x^4)^(3/4))

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Maple [F]  time = 0.031, size = 0, normalized size = 0. \[ \int{\frac{1}{{x}^{3}} \left ( -b{x}^{4}+a \right ) ^{-{\frac{3}{4}}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int(1/x^3/(-b*x^4+a)^(3/4),x)

[Out]

int(1/x^3/(-b*x^4+a)^(3/4),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (-b x^{4} + a\right )}^{\frac{3}{4}} x^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(1/((-b*x^4 + a)^(3/4)*x^3),x, algorithm="maxima")

[Out]

integrate(1/((-b*x^4 + a)^(3/4)*x^3), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (\frac{1}{{\left (-b x^{4} + a\right )}^{\frac{3}{4}} x^{3}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(1/((-b*x^4 + a)^(3/4)*x^3),x, algorithm="fricas")

[Out]

integral(1/((-b*x^4 + a)^(3/4)*x^3), x)

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Sympy [A]  time = 3.27207, size = 32, normalized size = 0.38 \[ - \frac{{{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{3}{4} \\ \frac{1}{2} \end{matrix}\middle |{\frac{b x^{4} e^{2 i \pi }}{a}} \right )}}{2 a^{\frac{3}{4}} x^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(1/x**3/(-b*x**4+a)**(3/4),x)

[Out]

-hyper((-1/2, 3/4), (1/2,), b*x**4*exp_polar(2*I*pi)/a)/(2*a**(3/4)*x**2)

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GIAC/XCAS [F]  time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (-b x^{4} + a\right )}^{\frac{3}{4}} x^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate(1/((-b*x^4 + a)^(3/4)*x^3),x, algorithm="giac")

[Out]

integrate(1/((-b*x^4 + a)^(3/4)*x^3), x)